3((x+1)/(x-1))^2+4((x+1)/(x-1))-4

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Solution for 3((x+1)/(x-1))^2+4((x+1)/(x-1))-4 equation:


D( x )

x-1 = 0

x-1 = 0

x-1 = 0

x-1 = 0 // + 1

x = 1

x in (-oo:1) U (1:+oo)

3*((x+1)/(x-1))^2+4*((x+1)/(x-1))-4 = 0

(3*(x+1)^2)/((x-1)^2)+(4*(x+1))/(x-1)-4 = 0

(3*(x+1)^2)/((x-1)^2)+(4*(x+1)*(x-1))/((x-1)^2)+(-4*(x-1)^2)/((x-1)^2) = 0

3*(x+1)^2+4*(x+1)*(x-1)-4*(x-1)^2 = 0

7*x^2-4*x^2+6*x+8*x-4-1 = 0

3*x^2+14*x-5 = 0

3*x^2+14*x-5 = 0

3*x^2+14*x-5 = 0

DELTA = 14^2-(-5*3*4)

DELTA = 256

DELTA > 0

x = (256^(1/2)-14)/(2*3) or x = (-256^(1/2)-14)/(2*3)

x = 1/3 or x = -5

(x+5)*(x-1/3) = 0

((x+5)*(x-1/3))/((x-1)^2) = 0

((x+5)*(x-1/3))/((x-1)^2) = 0 // * (x-1)^2

(x+5)*(x-1/3) = 0

( x+5 )

x+5 = 0 // - 5

x = -5

( x-1/3 )

x-1/3 = 0 // + 1/3

x = 1/3

x in { -5, 1/3 }

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